Relativistic electrons and positrons

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SUMMARY

The discussion centers on a physics problem involving the collision of an electron and positron, each with a rest mass energy of 511 keV, resulting in the creation of a proton and antiproton with rest mass energy of 938 MeV. The minimum kinetic energy required for both the electron and positron to achieve this reaction is calculated to be 937.5 MeV. A common misconception regarding the speed of the electron was addressed, clarifying that using the relativistic energy equation correctly shows the electron moving at 0.9999998c, not exceeding the speed of light.

PREREQUISITES
  • Understanding of relativistic energy equations, specifically E = T + mc²
  • Knowledge of particle physics, particularly electron and positron interactions
  • Familiarity with the concept of rest mass energy and its calculations
  • Basic grasp of relativistic velocity calculations and the implications of approaching light speed
NEXT STEPS
  • Study the derivation and implications of the relativistic kinetic energy formula, T = mc²/(√(1-v²/c²) - 1)
  • Explore particle collision experiments and their significance in high-energy physics
  • Learn about the conservation of energy and momentum in particle physics
  • Investigate the theoretical limits of particle speeds and the implications of special relativity
USEFUL FOR

This discussion is beneficial for physics students, educators, and researchers interested in particle physics, relativistic mechanics, and energy-momentum conservation principles.

mangojuice14
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Homework Statement


The question states that an electron and positron, each with rest mass energy of 511keV collide head on and create a proton and antiproton each with rest mass energy 938MeV. The question asks us to find the minimum kinetic energy of the electron and positron.

Homework Equations


Relativistic energy: E = T + mc2 where T is the kinetic energy.

The Attempt at a Solution


I have solved the problem with the relativistic energy equations by setting the proton's and antiproton's final state at rest
T(electron) +mec2 = mpc2
and obtained the solution that the electron and positron each would need a kinetic energy of 937.5MeV.

I checked the answer and it's correct but the energy implies that the electron would be moving at 60 times light speed. Does this mean the problem is purely theoretically and is not physically possible or am I missing something. Thanks
 
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mangojuice14 said:
Welcome to PF!

I checked the answer and it's correct but the energy implies that the electron would be moving at 60 times light speed.
Can you show your calculation for this? Remember, the formula for kinetic energy, T, in relativity is not (1/2)mv2.
You should be able to show that an electron with any finite amount of energy (no matter how large) would still move at less than the speed of light.
 
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TSny said:
Can you show your calculation for this? Remember, the formula for kinetic energy, T, in relativity is not (1/2)mv2.
You should be able to show that an electron with any finite amount of energy (no matter how large) would still move at less than the speed of light.

Oh right! I was actually using the small velocity approximation...woops. Using $$E = \frac {mc^2} {\sqrt{1-\frac{v^2}{c^2}}}$$ where E would be 938MeV, I now obtain a speed of 0.9999998c. Thanks!
 

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