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Another Action/Reaction question Donkey and a cart

  1. Oct 2, 2006 #1
    Another Action/Reaction question...Donkey and a cart!!!

    Hey, i am doing this for prety much basic physics but i need to:

    Draw all the action-reaction pairs.
    If the cart pulls on the mule with the same force that the mule pulls on the cart, how can the mule move?

    [​IMG]

    Can you help me out?!?!

    Thanks
    John

    The mule would pull it if it exerted more force than the cart puts onto the mule, Right?

    Also, are there only F1 and -F1, or are there gravity forces that act as action reaction forces?
     
    Last edited: Oct 2, 2006
  2. jcsd
  3. Oct 2, 2006 #2
    Objects don't move if the net force on them is zero.

    Do the forces in the diagram act on the same object?

    Draw the net forces on the objects in the diagram. Think about which way each object would move.

    In this case, we can assume that there is friction, because otherwise the mule would get nowhere. It would tread along the ground, but it would not move forward. Gravity is also there, but it is pretty much irrelevant.

    The ground pushes the mule forward when the mule pushes against the ground to take steps, because of friction.

    This problem is very important to understand, because otherwise free-body diagrams become confusing.
     
  4. Oct 2, 2006 #3
    so in order for the mule to pull the cart, there would obviously have to be friction, and it would have to have a force greater than the cart.

    But what would the diagram look like for this situation?
     
  5. Oct 2, 2006 #4
    The forces on the horse and the cart that are labeled in the diagram do not affect the horse's moving forward. It is the forces between the horse and the ground that matter.

    Think about that when you draw the diagram.
     
  6. Oct 2, 2006 #5
    well its not the only action and reaction force on the cart
    there is another action and reaction force couple
    which the donkey is applying
    he is applying force downward and backward
    and the reaction force is acting forward and upward
    so thats why it moves .......
     
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