Another change in unit vectors (d(r-hat)/d(theta)) in Cylindrical

  • #1

Homework Statement



Does anyone know what d(r-hat)/d(theta) in Cylindrical coordinates is?


Homework Equations





The Attempt at a Solution



I'm pretty sure its -(theta-hat) but I'm not sure, any help?

Thanks so much
 
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  • #2
so theta is moved over by d(theta) shifting over r-hat and theta-hat.. What would d(r-hat)/d(theta) be?
 
  • #3
anyone? :)
 
  • #4
Hi khfrekek1992! :smile:

[tex]{d\hat r \over d\theta} = \hat \theta[/tex]

If you draw [itex]\hat r[/itex] for 2 angles, you'll see that the vector-difference between them points in the direction of [itex]\hat \theta[/itex].
Its (approximate) length is [itex]d\theta[/itex].
 
  • #5
Oh! I see how you get that now.. Thanks so much! That helps a ton :D
 

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