Another differentiation question

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SUMMARY

The discussion focuses on differentiating functions involving a differentiable function "f". For the function h(x) = -4x^3 * f(x), the derivative is h'(x) = -4x^3 * f'(x) - 12x^2 * f(x), applying the product rule. For h(x) = 2/√x * f(x), the derivative is h'(x) = (2/√x) * f'(x) - (1/x^(3/2)) * f(x). The participants confirm the application of the product rule and clarify the differentiation process.

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Homework Statement



Supposed "f" is a differentiable function. Write the expression for the derivative of the following function.

a) h(x) = -4x^3 * f(x)

b) h(x) = 2/[tex]\sqrt{x}[/tex]* f(x)

Homework Equations



N/a

The Attempt at a Solution



Would the answers just be (using the product rule)

a) h'(x) = -4x^3 * f '(x) + f(x) * -12x^2

and

b) h'(x) = 2/[tex]\sqrt{x}[/tex] * f '(x) + f(x) * -x^-2


Sort of seems to simple... Thanks again
 
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a) Yes, b) [tex]\frac{2}{\sqrt{x}}[/tex] is not [tex]\frac{-1}{x^2}[/tex]
 
Last edited:

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