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elsternj
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Homework Statement
On a horizontal, frictionless table, an open-topped 5.50kg box is attached to an ideal horizontal spring having force constant 365 N/m . Inside the box is a 3.44-kg stone. The system is oscillating with an amplitude of 7.50 . When the box has reached its maximum speed, the stone is suddenly plucked vertically out of the box without touching the box.
Find the period of the resulting motion of the box.
Homework Equations
T = 2pi[tex]\sqrt{m/C}[/tex]
The Attempt at a Solution
okay well for the first half of the period the mass is 3.44+5.5 = 8.94
.5T = 2pi[tex]\sqrt{8.94/365}[/tex] = .983
then the stone is thrown out
.5T = 2pi[tex]\sqrt{5.5/365}[/tex] = .771
.771 + .983 = 1.75s
wrong. I am new to this harmonic motion so I could be way off. any guidance?