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## Homework Statement

A 0.26-kg block on a horizontal frictionless surface is attached to an ideal massless spring whose spring constant is 190 N/m. The block is pulled from its equilibrium position at

*x*= 0.00 m to a displacement

*x*= +0.080 m and is released from rest. The block then executes simple harmonic motion along the horizontal

*x*-axis. When the displacement is

*x*= 1.4×10−2 m, what is the kinetic energy of the block?

## Homework Equations

KE=1/2mw^2A^2sin^2(wt+phi)

a=(k/m)x

w=(k/m)^1/2

## The Attempt at a Solution

I have everything for the equation except for phi and and the amplitude A. I have found a=10.23 m/s2 and w=27.0327rad/s but I am stuck on how to find phi and A. Is there a relationship between the initial equilibrium position for finding A or phi?

Thanks for the help!