Another logarithm simplification exercise.

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Homework Help Overview

The discussion revolves around simplifying a logarithmic expression, specifically log_{10}\frac{3}{\sqrt{1+x}}, into sums and differences of simpler logarithmic forms without using products, quotients, or powers in the final expression.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the correct interpretation of the original logarithmic expression and question the accuracy of the book's provided answer. There is a focus on ensuring the numerator is correctly understood as just 3, rather than involving an exponential term.

Discussion Status

The conversation is ongoing, with participants examining potential discrepancies between the problem statement and the book's answer. Some suggest that there may be a typographical error in the answer key, while others confirm the original problem as stated.

Contextual Notes

There is a concern regarding the clarity of the problem statement and the possibility of misinterpretation, particularly about the numerator of the logarithmic expression.

0range
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Homework Statement



Write the quantity using sums and differences of simpler logarithmic expressions. Express the answer so that logarithms of products, quotients, and powers do not appear.

log_{10}\frac{3}{\sqrt{1+x}}


Homework Equations





The Attempt at a Solution



2czc1sh.jpg


The book's answer, however, is 3log_{10}x-\frac{1}{2}log_{10}(1+x)

Thanks in advance!
 
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0range said:

Homework Statement



Write the quantity using sums and differences of simpler logarithmic expressions. Express the answer so that logarithms of products, quotients, and powers do not appear.

log_{10}\frac{3}{\sqrt{1+x}}


Homework Equations





The Attempt at a Solution



2czc1sh.jpg


The book's answer, however, is 3log_{10}x-\frac{1}{2}log_{10}(1+x)

Thanks in advance!

Check the original question to make sue the numerator is just 3 and not an exponential
 
Hi, thanks for the reply.

No, the original equation is as appears.
 
Must be a typo in the book, then. Possibly whoever typed up the answer key thought that the problem was
log_{10}\frac{x^3}{\sqrt{1+x}}
 
Oh, so I'm right? How anti-climatic...

Thanks again.
 

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