Solve Log Law Problems Homework Statement

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Homework Help Overview

The discussion revolves around simplifying expressions involving logarithms using logarithmic laws. Participants are working with specific logarithmic expressions and attempting to rewrite them as single logarithms.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants share their attempts to simplify logarithmic expressions, questioning the correctness of their methods. There are discussions on applying logarithmic properties, such as the product and quotient rules, and participants seek clarification on specific steps in their reasoning.

Discussion Status

Some participants have confirmed the correctness of certain simplifications, while others are encouraged to reconsider their approaches based on logarithmic properties. Multiple interpretations of the problems are being explored, and there is a mix of confirmations and suggestions for reworking answers.

Contextual Notes

Participants are navigating through the constraints of homework rules, focusing on the application of logarithmic laws without providing complete solutions. There is an emphasis on ensuring the correct application of properties in their simplifications.

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Homework Statement

Write as a single logarithm:

Homework Equations



Logarithm Laws:

log_a(xy) = log_a(x) + log_a(y)

log_a(\frac{x}{y}) = log_a(x) - log_a(y)
___________

Problem Set:

log_{10}A + log_{10}B - log_{10}C

\frac{1}{2}logX - 2log4

2logN + 3logX

The Attempt at a Solution



I simplified the first question to log_{10}(\frac{AB}{C}) Am I correct?

I wasn't sure about how to approach the second question. I multiplied \frac{1}{2} by X and 2 by 4 and simplified as follows:

log_{10}{\frac{1}{2}X} - log_{10}8

to get log_{10}(\frac{0.5x}{8})

I'm not sure if this is correct though.

If it is wrong, how would I solve it correctly?

For the third problem, I solved it to:

log_{10}[ (2n)(3x) ]

Thanks,
 
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Your AB/C is correct.

For the 1/2 log X you haven't listed the loglaw for it which is:

C * log (x) = log (x^C)

given that rework your answer.
 
AbsoluteZer0 said:
I simplified the first question to log_{10}(\frac{AB}{C}) Am I correct?

Yes..Thats right.

AbsoluteZer0 said:
I wasn't sure about how to approach the second question. I multiplied \frac{1}{2} by X and 2 by 4 and simplified as follows:

log_{10}{\frac{1}{2}X} - log_{10}8

to get log_{10}(\frac{0.5x}{8})

I'm not sure if this is correct though.

If it is wrong, how would I solve it correctly?

For the third problem, I solved it to:

log_{10}[ (2n)(3x) ]

Thanks,

That is not the correct way .

Use the following property of logarithms : logb(xn) = n logbx.
 
I solved the second one to:

log_{10}\frac{X^{0.5}}{16}

Is this correct?

Thanks
 
AbsoluteZer0 said:
I solved the second one to:

log_{10}\frac{X^{0.5}}{16}

Is this correct?

Thanks

Correct
 
And would the second one be

log_{10}(N^2X^3)?

Thanks
 
AbsoluteZer0 said:
And would the second one be

log_{10}(N^2X^3)?

Thanks

:thumbs:
 
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Thank you very much!
 
dont forget to use the Thanks button to thank everyone.
 
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