Another Planetary Mechanics Question

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SUMMARY

The discussion centers on calculating the orbital period of a NASA spaceship orbiting the moon at an altitude of 111 km. The user applied the equation mp=4π²R³/GT², using the moon's mass (7.36×1022 kg) and the total radius (1,848,000 m) to derive an orbital period of approximately 7120 seconds. The calculation was confirmed to be on the right track, although the user expressed uncertainty about the equation's derivation and potential energy concepts, which were not yet covered in their coursework.

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NDiggity
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Homework Statement


A NASA spaceship is orbiting the moon at an altitude of 111 km. How long does it take the ship to make one orbit around the moon?

This was a question on the test I had today, just wondering if I'm out to lunch or not. So he gave us all the info on the moon on an overhead. I used the mass of the moon 7.36*10^22 kg and the radius 1,737,000m added to the altitude.

Homework Equations


I used the equation mp=4π²R³/GT²

The Attempt at a Solution


So I plugged in 7.36*10^22=4π²(1848000)³/6.67*10¯¹¹(T²) and solved for t.

I got with sig figs 7120 seconds or something like that on the test. His numbers might have been slightly different. Did I do this completely wrong?
 
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I'm not familiar with the equation that you are using, that is to say that it must be derived from a couple of other equations, but it could be correct.

I would have used potential energy to find the angular velocity, and then the period. Just approximating in my mind, I think you are right or close to right.
 
Alright well thank you for your help. We have not learned about potential energy yet but if you think my answer is in the ballmark, that makes me worry a lot less!
 

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