Answer: Calculating Lattice Binding Energy of MgO Crystal

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The discussion focuses on calculating the total binding energy of the Mg ion in a MgO crystal lattice, where Mg is surrounded by six oxygen atoms. The user is attempting to apply Coulomb's law to find the attractive force and balance it with the repulsive force at equilibrium. However, confusion arises regarding the interpretation of the binding energy, with the user questioning whether the question pertains to electron binding energy instead. The user expresses difficulty in determining the total binding energy due to the net force being zero at equilibrium. Clarification on the correct approach to calculating binding energy in this context is sought.
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Homework Statement



In a crystal lattice of MgO, the Mg is surrounded by 6 Oxygen atoms as shown.
Assume that the ions all behave as point charges.

If the system behaves as though there were separate interactions between Mg and each of
the Oxygen ions what is the total binding energy of the Mg ion?

Homework Equations



F_c = -K/a^2
F=\frac{dE}{da}
F=F_c+F_R


The Attempt at a Solution



so I'm quite confused with this question.

I can find the coulombic force of attraction using F_c = -K/a^2 if i take a to be the equilibrium bond length and look up values for the ionic radii.

Now that i know the attraction force i can then work out the repulsive force as at the equilibrium bond length the attractive force is balanced by the repulsive force.

my problem is that because the forces balance the net force is zero , so what is the total binding energy of the iron.
 
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would anyone agree that the question is asking for the electron binding energy and that i was trying to find the wrong thing?

im still stuck with this.

Thanks
Sean
 

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