MHB Answer: Solving Algebra Problems: du=-30x^2dx to x^2 dx = -(1/30)du

[student231]

Hello,

Having a lapse in memory how was this 1) changed into 2) algebraically

1) du=-30x^2dx

2) x^2 dx = -(1/30)du thank you for any help.

 

[MarkFL]

Hello,

Having a lapse in memory how was this 1) changed into 2) algebraically

1) du=-30x^2dx

2) x^2 dx = -(1/30)du thank you for any help.

It appears both sides were divided by -30, or equivalently, multiplied by $$-\frac{1}{30}$$, and then arranged as shown. Does that make sense?