Answer: Solving Algebra Problems: du=-30x^2dx to x^2 dx = -(1/30)du

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SUMMARY

The algebraic transformation from the equation du = -30x²dx to x²dx = -(1/30)du is achieved by dividing both sides by -30. This operation effectively isolates x²dx on one side of the equation, resulting in the rearranged form. The manipulation is straightforward and relies on basic algebraic principles of division and rearrangement.

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Hello,

Having a lapse in memory how was this 1) changed into 2) algebraically

1) du=-30x^2dx

2) x^2 dx = -(1/30)du thank you for any help.
 
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student231 said:
Hello,

Having a lapse in memory how was this 1) changed into 2) algebraically

1) du=-30x^2dx

2) x^2 dx = -(1/30)du thank you for any help.

It appears both sides were divided by -30, or equivalently, multiplied by $$-\frac{1}{30}$$, and then arranged as shown. Does that make sense?
 

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