Antiderivative to the formula f(x)=(2xr-x²)^(1/2)

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    Antiderivative Formula
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Discussion Overview

The discussion revolves around finding the antiderivative of the function f(x) = (2xr - x²)^(1/2). Participants explore various approaches and share resources related to antiderivatives.

Discussion Character

  • Homework-related, Exploratory, Technical explanation

Main Points Raised

  • One participant expresses difficulty in finding the antiderivative and seeks assistance.
  • Another participant provides a proposed antiderivative, including a complex expression involving square roots and inverse tangent.
  • A different participant comments on the complexity of the integral, indicating it may be challenging to approach.
  • One participant suggests that the integral resembles a form that could be solved using arcsin after completing the square.
  • Another participant mentions a specific range for integration, indicating a trial-and-error approach.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the best method for finding the antiderivative, and multiple approaches are discussed without resolution.

Contextual Notes

Some participants reference specific techniques and forms, but there is no agreement on the correctness of the proposed solutions or methods. The discussion includes varying levels of complexity and assumptions about the function.

Who May Find This Useful

Individuals interested in calculus, particularly those working on antiderivatives and integral calculus problems.

greghouse
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Hi, i can't seem to get the antiderivative to the formula f(x)=(2xr-x²)^(1/2) right. Can anyone help me out?

By the by, if could anyone link a site with formulas for antiderivatives that would be nice.
 
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The anti-derivative you are seeking is:

<br /> \frac{2 r^2 \sqrt{2 r-x} \sqrt{x} \tan ^{-1}\left(\frac{\sqrt{x}}{\sqrt{2 r-x}}\right)-x \left(2 r^2-3 x r+x^2\right)}{2 \sqrt{(2<br /> r-x) x}}<br />

I highly recommend this site:

http://integrals.wolfram.com/index.jsp

And I highly recommend the software package Mathematica that is made by this company.
 
Ouch. That integral hurts a lot. I wonder how to even begin doing it.
 
well off hand it just looks like sqrt(a^2 - u^2), after completing the square, which would make it an arcsin.
 
Damn! I was going to intergral from 0 to 2r... Trial and error
 

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