Where did I go wrong with my working? The answer in the book is(adsbygoogle = window.adsbygoogle || []).push({});

f(t) = t^2 + 3 cos t + 2

1. The problem statement: Find f for

f prime (t) = 2t - 3 sin t, f(0) = 5

2. Relevant equations:

Most General antiderivation: F(x) + C

Antidifferentiation formula: Function = sin x, Particular antiderivation = -cos x

3. My attempt at a solution

= [(2t^2)/2] -3 (-cos) t + C

= t^2 + 3 cos t + C

f(0) = t^2 + 3 cos t + C = 5

Therefore C = 5 - (0)^2 + 3 cos (0)

C = 5

Therefore f(t) = t^2 - 3 cos t + 5

Why is this answer wrong?

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# Antiderivatives (where did I go wrong?)

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