willy0625
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Any point in 3-dimensional space
Is is possible to write any point {\bf x}\in \mathbb{R}^{3} as a linear combination of vectors {\bf v_{j}} inside the unit ball over \mathbb{R} given that
\sum_{j}c_{j}{\bf v_{j}}
can be made arbitrarily small?
My approach was letting
\parallel{\bf x}\parallel \leq \bigg{\parallel} \sum_{j}c_{j}{\bf v_{j}}\bigg\parallel (*)
Then applying the triangle inequality to the two terms then (*), the triangle inequality again to the linear combination, \parallel v_{j}\parallel<1 for all n then the Cauchy's inequality to obtain
\parallel{\bf x} - \sum_{j}c_{j}{\bf v_{j}}\bigg\parallel
\leq 4n\sum_{j}|c_{j}|^{2}
where n is the number of terms in the linear combination, which is finite.
Therefore by letting \sum_{j}|c_{j}|^{2} \rightarrow 0,
we get
\parallel{\bf x}- \sum_{j}c_{j}{\bf v_{j}}\bigg\parallel \leq 0
Thus deducing
{\bf x} = \sum_{j}c_{j}{\bf v_{j}}
I am not sure if assuming (*) is the correct way of doing this since we miss out on the other possibility (>).
Is is possible to write any point {\bf x}\in \mathbb{R}^{3} as a linear combination of vectors {\bf v_{j}} inside the unit ball over \mathbb{R} given that
\sum_{j}c_{j}{\bf v_{j}}
can be made arbitrarily small?
My approach was letting
\parallel{\bf x}\parallel \leq \bigg{\parallel} \sum_{j}c_{j}{\bf v_{j}}\bigg\parallel (*)
Then applying the triangle inequality to the two terms then (*), the triangle inequality again to the linear combination, \parallel v_{j}\parallel<1 for all n then the Cauchy's inequality to obtain
\parallel{\bf x} - \sum_{j}c_{j}{\bf v_{j}}\bigg\parallel
\leq 4n\sum_{j}|c_{j}|^{2}
where n is the number of terms in the linear combination, which is finite.
Therefore by letting \sum_{j}|c_{j}|^{2} \rightarrow 0,
we get
\parallel{\bf x}- \sum_{j}c_{j}{\bf v_{j}}\bigg\parallel \leq 0
Thus deducing
{\bf x} = \sum_{j}c_{j}{\bf v_{j}}
I am not sure if assuming (*) is the correct way of doing this since we miss out on the other possibility (>).
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