Hermitian Adjoint of V & R Vector Spaces Homework

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SUMMARY

The discussion focuses on calculating the Hermitian adjoint of linear maps in the context of Euclidean vector spaces. Specifically, it addresses the map \( j: \mathbb{R} \to V \) defined by \( r \mapsto rX \) and the linear map \( \Phi: V \to \mathbb{R} \) that sums coefficients of polynomials. The Hermitian adjoint \( j^* \) is derived as \( j^*(f) = f(1) - f(-1) \). The discussion also emphasizes the importance of verifying the inner product equality for correctness.

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Homework Statement



Be V the set ##\{f \in \mathbb{R}[X]| deg\,f \leq 2 \}##. This becomes to an euclidic vector space through the
inner product ##\langle f,g\rangle:=\sum_{i=-1}^1f(i)g(i)## .
The same goes for ##\mathbb{R}## with the inner product ##\langle r,s\rangle :=rs\,\,\,##.

a) For ##j:\mathbb{R}\to V,r\mapsto rX##, calculate the hermitian adjoint ##j^*##.

b) Be ##\Phi :V \to \mathbb{R}## the linear map ##\sum_{i=0}^2a_iX^i \mapsto \sum_{i=0}^2a_i \,\,\,##. Calculate the hermitian adjoint ##\Phi^*\,\,\,##.

Homework Equations



The Attempt at a Solution


For a) i have the follwowing solution:

##\langle f,j(s) \rangle_V = \langle j^*(f), s \rangle_{\mathbb{R}}##
##\Rightarrow \sum_{i=-1}^1f(i) \cdot (j(s))(i)=j^*(f) \cdot s##
##\Rightarrow f(-1)\cdot -s+f(0)\cdot 0s+f(1)\cdot s = j^*(f) \cdot s##
##\Rightarrow j^*(f)=f(1)-f(-1)##

Is this solution correct?
For b), i don't find a starting point.
 
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Can't we approach (b) the same way as (a)?
For (b), the defining equation is
$$\langle\Phi(f),s\rangle=\langle f,\Phi^*(s)\rangle$$
What happens if we expand that using the definitions given?

Your working for (a) looks broadly correct. To check that something has not gone wrong, like a missed sign, plug a polynomial ##f(x)=a_0+a_1x+a_2x^2## into it and see if the equality of the two inner products holds.
 

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