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I am calculating the one loop vacuum energy in the Wess-Zumino model, and I don't get a cancellation. For sure I've messed up with the symmetry factor for the boson diagram, because in the fermion sector i have the cancellation (that is almost trivial). I an old post 2 guys were discussing of the 2-loop check, but would be nice for me to see the explicit cancellation for the original lagrangian of wess-zumino at 1-loop.
I say in advance that I know that in superfields formalism the problem of susy UV cancellations is almost straightforward and that it's possible to go easily to higher loop calculations for simple models like the Wess-Zumino, but I would like to get rid of this problem, because it makes me think that I can not calculate the symmetry factor!
The original lagrangian of wess-zumino in component is in the euclidean:
L= 1/2g^2(A^2+B^2)^2+Mg(A^3+AB^2)+A\bar{\psi}\psi+igB\bar{psi}\gamma_{5}\psi
thanks for your attention
I say in advance that I know that in superfields formalism the problem of susy UV cancellations is almost straightforward and that it's possible to go easily to higher loop calculations for simple models like the Wess-Zumino, but I would like to get rid of this problem, because it makes me think that I can not calculate the symmetry factor!
The original lagrangian of wess-zumino in component is in the euclidean:
L= 1/2g^2(A^2+B^2)^2+Mg(A^3+AB^2)+A\bar{\psi}\psi+igB\bar{psi}\gamma_{5}\psi
thanks for your attention