# Anyone remember how to solve 0^0?

1. Jul 27, 2012

### kings_gambit

I remember it was 'one', but it's been a while...basically we want to find

lim (as x-->0) of (x^x), or not? Any takers?

Cheers,

2. Jul 27, 2012

### DonAntonio

There's nothing "to solve". This is a problematic expression which in basic maths is almost always left undefined, and

sometimes, under some usually rather astringent conditions, it is defined as 1 because certainly
$$x^x=e^{x\log x}\xrightarrow [x\to 0^+]{} e^0=1$$

Play attention to the fact the function isn't defined over the negative reals, unless you'd be wishing to get into multivalued complex functions and stuff.

DonAntonio

3. Jul 27, 2012