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Anyone remember how to solve 0^0?

  1. Jul 27, 2012 #1
    I remember it was 'one', but it's been a while...basically we want to find

    lim (as x-->0) of (x^x), or not? Any takers?

  2. jcsd
  3. Jul 27, 2012 #2

    There's nothing "to solve". This is a problematic expression which in basic maths is almost always left undefined, and

    sometimes, under some usually rather astringent conditions, it is defined as 1 because certainly
    [tex]x^x=e^{x\log x}\xrightarrow [x\to 0^+]{} e^0=1[/tex]

    Play attention to the fact the function isn't defined over the negative reals, unless you'd be wishing to get into multivalued complex functions and stuff.

  4. Jul 27, 2012 #3
    Please read https://www.physicsforums.com/showthread.php?t=530207 [Broken]
    Last edited by a moderator: May 6, 2017
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