AP Mag Problem: 2.0keV Positron in 0.10T Field - Find Period, Pitch, Radius

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The discussion focuses on calculating the motion of a 2.0 keV positron in a uniform magnetic field of 0.10 T. The key results include a period of 3.6e-10 seconds, a pitch of 1.63e-4 meters, and a radius of 1.48e-3 meters. The calculations involve resolving the velocity vector into horizontal and vertical components and applying the relationship between magnetic force and centripetal force.

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Physicsisfun2005
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A 2.0 keV positron is projected into a uniform magnetic field B of 0.10 T with its velocity vector making an angle of 89 degrees with B. Find
a. the period
b. the pitch p
c. the radius of the helix


We have never done a problem similar to this in class so I'm am not sure where to start...
 
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Here's a hint:

\v{F} = Q ( \v{E} + \v{u} x \v{B} ) = \frac{m v^2}{r}
 
Last edited:
The 2.0 keV is the kinetic energy of the particle, from which you can get the speed (but remember to convert to joules).
 
ahhh...mag force = centripital force
 
Physicsisfun2005 said:
ahhh...mag force = centripetal force
Oui!
Ja!
Yes!
 
"pitch"? :confused:
 
Brad Barker said:
"pitch"? :confused:
If you look at a spring that is hanging vertically, you can see that it winds "up" to the right or to the left with a certain angle to the horizontal. This angle is the pitch. THe path of a charged object traveling through a magnetic filed will also be a helix (like a spring).
 
we went over it in class and i got the correct answers :smile:

if u want to know here they are:

a. period is 3.6e-10 sec.
b.pitch is 1.63e-4 m
c.radius is 1.48e10-3 m

Was easy once I figured that i needed to resolve the velocity vector in horizontal and vertical components :smile:
 

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