A single ionized uranium ion of mass 6.9 x 10 ^-25 kg is accelerated through a potential difference of 4.4 x 10^5 V.
What is the radius of the path it would take if injected at 90 degrees into 0.47 T uniform magnetic field at this velocity?
Since centripetal force is equal to magnetic force, I tried using the formula of m(v^2)/r = Bqv
By rearranging this, I was able to isolate for the radius mv/Bq = r
I used these values, in the the formula to find the radius
(4.4 x 10^5 V)(6.9 x 10 ^-25 kg) / (0.47T)(1.6 * 10^-19)
The answer I got was 4.037 m, however this is wrong because the real answer is 4.14m. I'm not sure what I am doing wrong, because the two values seem really close