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Magnetic Fields- Finding the radius

  1. Apr 17, 2017 #1
    1. The problem statement, all variables and given/known data
    A single ionized uranium ion of mass 6.9 x 10 ^-25 kg is accelerated through a potential difference of 4.4 x 10^5 V.
    What is the radius of the path it would take if injected at 90 degrees into 0.47 T uniform magnetic field at this velocity?

    3. Attempts

    Since centripetal force is equal to magnetic force, I tried using the formula of m(v^2)/r = Bqv

    By rearranging this, I was able to isolate for the radius mv/Bq = r

    I used these values, in the the formula to find the radius
    (4.4 x 10^5 V)(6.9 x 10 ^-25 kg) / (0.47T)(1.6 * 10^-19)

    The answer I got was 4.037 m, however this is wrong because the real answer is 4.14m. I'm not sure what I am doing wrong, because the two values seem really close

    Thank you
     
  2. jcsd
  3. Apr 17, 2017 #2

    kuruman

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    It's probably a round off issue. How did you find v?
     
  4. Apr 17, 2017 #3
    I used the potential difference of 4.4 x 10^5 V as my V
     
  5. Apr 17, 2017 #4

    kuruman

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    That's a problem. The "v" in qvB and in mv2/r is a speed, not a potential difference. You need to find the speed from the potential difference. Hint: Use energy conservation.
     
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