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## Homework Statement

A single ionized uranium ion of mass 6.9 x 10 ^-25 kg is accelerated through a potential difference of 4.4 x 10^5 V.

What is the radius of the path it would take if injected at 90 degrees into 0.47 T uniform magnetic field at this velocity?

**3. Attempts**

Since centripetal force is equal to magnetic force, I tried using the formula of

**m(v^2)/r = Bqv**

By rearranging this, I was able to isolate for the radius

**mv/Bq = r**

I used these values, in the the formula to find the radius

(4.4 x 10^5 V)(6.9 x 10 ^-25 kg) / (0.47T)(1.6 * 10^-19)

The answer I got was 4.037 m, however this is wrong because the real answer is 4.14m. I'm not sure what I am doing wrong, because the two values seem really close

Thank you