AP Physics B - Satellite/Orbit problem?

In summary, the satellite has a potential energy of -GMem when it is a distance r from the center of the Earth, and a change in energy of 1/2mv^2 when it is in its circular orbit. The speed of the satellite when it is in its circular orbit is vo.
  • #1
ohmygosh123
2
0
A satellite of mass m is in an elliptical orbit around the Earth, which has mass Me and radius Re. The orbit varies from closest approach of a at point A to maximum distance of b from the center of the Earth at point B. At point A, the speed of the satellite is vo.Express your answers in terms of a, b, m, Me, Re, vo, and G.

a. Write the expression for the gravitational force between the satellite and Earth at point b.

b. The potential energy of the satellite when it is a distance r from the center of the Earth is given by:

Ug=(-GMem)/r

Determine the total energy of the satellite when it is at A.


c. Determine the velocity of the satellite as it passes point B in its orbit.


As the satellite passes point A, a rocket engine on the satellite is fired so that its orbit is changed to a circular orbit of radius a about the center of the Earth.

d. determine the speed of the satellite for this circular orbit.


e. calculate the work done in changing the orbit



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I honestly don't know where to start with this problem...any initial help would be very much appreciated :)
 
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  • #2
Hi ohmygosh123 welcome to PF!

Please show an attempt at the question, like a relevant equations and what you think should be the correct way to solve this problem.

-yinx-
 
  • #3
Ok this is what i have so far:

A: Fg = (GmM)/r^2 = (GmMe)/bRe^2

B: Total Energy = KE + PE = (-GMem)/a + 1/2mvo^2

C: (-GMem)/a + 1/2mvo^2 = 1/2mv^2 ?

D: change in KE = 1/2mv^2 - 1/2mvo^2 => 2(change in KE) = mv^2 - mvo^2

E: W = Fdcos / W = Change in KE or Change in Energy / W = 1/2mv^2 - 1/2mvo^2

W = m[(v^2-vo^2)/2]



I have no idea where to go from there! Please HELPP!
 

Related to AP Physics B - Satellite/Orbit problem?

1. What is the difference between a geostationary and a polar orbit?

A geostationary orbit is an orbit in which a satellite stays above a fixed point on the Earth's equator, appearing to be stationary from the ground. A polar orbit, on the other hand, is an orbit in which a satellite passes over the North and South poles on each revolution around the Earth.

2. How is the speed of a satellite related to its orbital radius?

The speed of a satellite is inversely proportional to its orbital radius. This means that as the orbital radius increases, the speed of the satellite decreases. This relationship is described by Kepler's Third Law of Planetary Motion.

3. Can a satellite have a circular orbit with a non-zero eccentricity?

No, a satellite cannot have a circular orbit with a non-zero eccentricity. A circular orbit is defined as having an eccentricity of 0, meaning the orbit is a perfect circle. An eccentricity of 0.01 or higher would result in an elliptical orbit.

4. How does the Earth's rotation affect satellite orbits?

The Earth's rotation affects satellite orbits in two ways. Firstly, the Earth's rotation causes the Coriolis force which can affect the direction of a satellite's orbit. Secondly, the Earth's rotation causes the equatorial bulge, which can perturb the orbit of a satellite if it is not in a polar orbit.

5. What is the difference between a synchronous and a geosynchronous orbit?

A synchronous orbit is an orbit in which a satellite completes one revolution around the Earth in the same amount of time as the Earth's rotation, resulting in the satellite appearing to be stationary from a fixed point on the Earth's surface. A geosynchronous orbit, on the other hand, is an orbit with an inclination of 0 degrees, meaning the satellite follows the same path over the Earth's equator on each revolution. A geosynchronous orbit is a type of synchronous orbit, but not all synchronous orbits are geosynchronous.

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