Ap physics gravitational force on satellites. Any help appreciated

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Homework Help Overview

The discussion revolves around gravitational forces acting on satellites, specifically calculating the gravitational force exerted by the Earth on a satellite at a certain distance from the Earth's center. The original poster presents a scenario involving a 450 kg satellite orbiting at a distance of about 6.5 Earth radii.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the gravitational force equation and the importance of using correct units, particularly ensuring distances are in meters. There are attempts to clarify calculations and ratios related to gravitational force at varying distances.

Discussion Status

Some participants have provided guidance on checking calculations and unit conversions. There is an ongoing exploration of different approaches to solving the problems presented, with some participants sharing their results and seeking clarification on their methods.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the sharing of complete solutions. There is a noted confusion regarding the setup of the equations and the interpretation of variables, particularly in the context of gravitational force calculations.

astru025
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1. Homework Statement


A 450 kg satellite orbits at a distance from the Earth's center of about 6.5 Earth radii. What gravitational force does the Earth exert on the satellite?
2. Homework Equations

Gravitational force= G* ((mMe)/(r^2))

3. The Attempt at a Solution
G times mass times Earth's mass divided by radius squared.
G= 6.67E-11
m= 450 kg
Me(Earth's mass)= 5.98E24
r(radius)= 6.5 x 6370 (Earth's radius)
I inserted this into the equation but came up with the wrong answer it said. I don't know what I'm doing wrong and am getting very frustrated !
 
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Make sure your distances are in meters.

Even easier would be to use ratios. By what factor is the weight of the object reduced when the distance is multiplied by 6.5?

(Please don't post the same thing twice!)
 
I made sure my distances were in meters and still cannot come up with the answer.
 
astru025 said:
I made sure my distances were in meters and still cannot come up with the answer.
What answer did you get?
 
I came up with 104964.74.
This is how I came up with that: G (6.67E-11 N*m^2/kg^2) times ((450 kg.) * (5.98E24 kg)) / (1.71E12 m)

I got 1.71E12 m by taking 6.5 times 6.37E6 and squaring that.
 
astru025 said:
I got 1.71E12 m by taking 6.5 times 6.37E6 and squaring that.
Redo that calculation; you are off by a factor of 1000.
 
Thank you so much. Fixed it and came up with a final answer of 103.75 and it was correct! Thanks so much!
 
You are very welcome. :thumbs:
 
I have another problem that is really challenging me and I was going to see if you could tell me what I'm doing wrong.
Problem: A 135 kg satellite experiences a gravitational force by the Earth of 960 N. What is the radius of the satellite's orbit?

I used the equation for gravitational force: F=G * ((m*Me) / (r^2)).
I put 135 in for m. 5.98E24 for Me( the Earth's mass), and for r I put in (x*6.4E6)^2. And I put 960 in for F.
I got an answer of 1.17 and it said it was wrong. And idea why? Thanks so much.
Reply
 
  • #10
One problem - one thread.
 
  • #11
astru025 said:
and for r I put in (x*6.4E6)^2
Why would you do that?
 
  • #12
6.4E6 is Earth's radius and then you square that. I'm not sure why I had that x in there.
 
  • #13
astru025 said:
6.4E6 is Earth's radius and then you square that. I'm not sure why I had that x in there.
r is the radius of the orbit; that's what you're solving for. So just leave it as "r" and solve for it.
 
  • #14
Thank you. I came up with 7489.99 and that was the correct answer!
 
  • #15
Now how do I find the altitude from this same problem?
 
  • #16
astru025 said:
Now how do I find the altitude from this same problem?
Altitude means how far above the earth. Hint: Make use of the Earth's radius.
 
  • #17
I'm so dumb. I subtract the Earth's radius (6370) from my radius and I got the correct answer! Thanks so much.
 

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