How do I solve this challenging AP Physics mechanics problem?

Click For Summary
The discussion centers on solving a challenging AP Physics problem involving a car's braking distance and reaction time. The problem presents two scenarios with different initial speeds and distances, prompting the need to establish relationships between them. Key formulas are provided, including V^2 = V0^2 - 2 * a * x, which can be adapted for each case to find the unknowns. The suggestion emphasizes writing equations for both scenarios to isolate reaction time and acceleration. This approach aims to clarify the mathematical relationships necessary for solving the problem effectively.
beeftrax
Messages
9
Reaction score
0
I'm doing an independent study in AP Physics, and am having a lot of trouble with the following problem:

"To stop a car, first you require a certain reaction time to begin braking; then the car slows under the constant braking deceleration. Suppose that the total distance moved by your car during these two phases is 56.7 m when its initial speed is 80.5 km/h, and 24.4 m when its initial speed is 48.3 km/h. What are (a) your reaction time and (b) the magnitude of the deceleration" (Fundamentals of Physics 6th ed; Halliday, Resnick, and Walker; pg 29, #37)

I've set the problem up, graphed the data, manipulated a lot of equations, and tried to solve it geometrically. I suspect that I need to use ratios to relate the two different situations, solve for reaction time, and use that to find acceleration, but I can't see how to do it.

Please Help!
 
Physics news on Phys.org
Greetings !

Use the formula: V^2 = V0^2 +/- 2 * a * x
V - final velocity
V0 - enitial velocity
-a/+a - de/acceleration
x - distance



How to solve : STOP ! DO NOT READ THIS UNLESS YOU TRIED
TO USE THE ABOVE FORMULA (with some small changes) AND
FAILED ! :wink:





Write the formula for each case. This is how it'll look :

1: V1^2 = V01^2 - 2 * a * (X1 - t * V01)
2: V2^2 = V02^2 - 2 * a * (X2 - t * V02)

X1/X2 - given distances
V01/V02 - given enitial velocities
t - reaction time (unknown)
a - acceleration (unknown)
V1/V2 - final velocities per case => V1 = V2 = 0

Live long and prosper.
 
Thanks! You've put my troubled mind at ease.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 29 ·
Replies
29
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
12K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K