How do I solve this challenging AP Physics mechanics problem?

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SUMMARY

The discussion focuses on solving a challenging AP Physics problem regarding a car's stopping distance, initial speeds, reaction time, and deceleration. The problem states that a car covers 56.7 m at an initial speed of 80.5 km/h and 24.4 m at 48.3 km/h. The solution involves applying the kinematic equations, specifically V^2 = V0^2 - 2 * a * (X - t * V0), to derive the reaction time and deceleration. The participants emphasize the importance of setting up the equations correctly for each scenario to find the unknowns.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of initial and final velocities
  • Familiarity with concepts of acceleration and deceleration
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the application of kinematic equations in real-world scenarios
  • Learn how to derive reaction time from motion equations
  • Explore the effects of varying initial speeds on stopping distances
  • Practice solving similar physics problems using different initial conditions
USEFUL FOR

Students preparing for AP Physics exams, educators teaching mechanics, and anyone interested in understanding the principles of motion and braking in vehicles.

beeftrax
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I'm doing an independent study in AP Physics, and am having a lot of trouble with the following problem:

"To stop a car, first you require a certain reaction time to begin braking; then the car slows under the constant braking deceleration. Suppose that the total distance moved by your car during these two phases is 56.7 m when its initial speed is 80.5 km/h, and 24.4 m when its initial speed is 48.3 km/h. What are (a) your reaction time and (b) the magnitude of the deceleration" (Fundamentals of Physics 6th ed; Halliday, Resnick, and Walker; pg 29, #37)

I've set the problem up, graphed the data, manipulated a lot of equations, and tried to solve it geometrically. I suspect that I need to use ratios to relate the two different situations, solve for reaction time, and use that to find acceleration, but I can't see how to do it.

Please Help!
 
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Greetings !

Use the formula: V^2 = V0^2 +/- 2 * a * x
V - final velocity
V0 - enitial velocity
-a/+a - de/acceleration
x - distance



How to solve : STOP ! DO NOT READ THIS UNLESS YOU TRIED
TO USE THE ABOVE FORMULA (with some small changes) AND
FAILED ! :wink:





Write the formula for each case. This is how it'll look :

1: V1^2 = V01^2 - 2 * a * (X1 - t * V01)
2: V2^2 = V02^2 - 2 * a * (X2 - t * V02)

X1/X2 - given distances
V01/V02 - given enitial velocities
t - reaction time (unknown)
a - acceleration (unknown)
V1/V2 - final velocities per case => V1 = V2 = 0

Live long and prosper.
 
Thanks! You've put my troubled mind at ease.
 

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