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Aphelion/Perihelion of Halleys comet

  1. Nov 24, 2005 #1
    Q.Halley's comet is in an elliptic orbit about the sun. The orbit eccentricity is 0.967 and the period is 76 years. Taking the mass of the sun to be [tex] 2 \times 10^30 kg[/tex] abd the usual value of G, determine the max and min distances of the comet from the sun.
    Now i've worked out teh answers but they differ from the values i've found on the net,(my guess is the value I've used for the solar mass isn't very accurate!) so would you mind taking a second to have a look at what i've done to see if i'm correct.
    [tex]a=( \frac{GM_{\odot}T^2}{4 \Pi ^2})^\frac{1}{3} [/tex]
    i got
    [tex]a= \sqrt[3]{ \frac{ (6.67 \times 10^-11 )( 2 \times 10^30 )( 2.4 \times 10^9)^2}{4 \Pi^2}}
    = 2.01 \times 10^9 m
    [tex]e= \frac{a-R_{min}}{a}
    R_{min} = 6.633\times1 0^6
    then to get R_max i used
    R_{max} = 2a - R_{min}
    = (2)(2.01\times10^9) - (6.633\times 10^6)
    = 2.666\times 10^{16} m
    the problem is i`ve found a value for R_min = 8.9x10^10 and R_max = 5.3x10^12 !
    Last edited: Nov 24, 2005
  2. jcsd
  3. Nov 24, 2005 #2


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    Homework Helper

    Check that calculation again. You have a power (-11 + 30 + 18)/3, it should be in the power 12 range.
  4. Nov 24, 2005 #3
    I`m blind to my own ignorance, thank you for pionting out the error.
  5. Feb 4, 2009 #4
    I am trying to figure out the speed of Halley's Comet in km/sec. at aphelion and perihelion

    I am using

    v² = (4Π²a³) / (P²) * ((2/r) - (1/a))

    where a = mean distance from the sun (semimajor axis of the ellipse)
    P= sidereal period (75 years)
    r = distance of the object from the Sun at a given instant

    a=16.8 A.U. c=16 A.U.

    "r" at perihelion = a-c "r" at aphelion = a + c
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