What Happens to a Comet's Orbit at Aphelion with Decreasing Angular Momentum?

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SUMMARY

The discussion focuses on the behavior of a comet's orbit at aphelion when its angular momentum approaches zero. As the angular momentum (l) decreases, the eccentricity (ε) of the comet's elliptical orbit approaches 1, indicating a transition to a parabolic trajectory. The equations used include c = l²/γμ for angular momentum, rmax = c/(1 - ε), and rmin = c/(1 + ε). Ultimately, as l approaches zero, the distance of closest approach (rmin) approaches zero, resulting in the comet moving directly towards the Sun.

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Homework Statement



Consider a comet which passes through its aphelion at a distance rmax from the sun. Imagine that, keeping rmax fixed, we somehow make the angular momentum l smaller and smaller though not actually zero; that is we let l\rightarrow0. Use equations c=l2/\gamma\ mu and rmax=c/1-\epsilon, rmin=1+\epsilonto show that in this limit the eccentricity, \epsilon of the elliptical orbit approaches 1 and the distance of closest approach rmin approaches zero.

Homework Equations



the equations posted above look funny, but for c it should be c=l2/gamma*mu
rmax=c/1-epsilon and rmin= c/1+epsilon.

The Attempt at a Solution


Well, I know that I am going to need to take limits. what i tried was to substitute in the c for the rmax equation, but then i really didn't know where to go from there. any help would be great.
 
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Well, physically what happened if you too l--> 0 What you reall did is take your orbital velocity to zero.

L = mV X R

You assumed aphelion, so R was fixed. Assuming mass went to zero would just make the commet float away. What wil happen is the commet will make a b-line straight for the sun.
 

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