(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

In a vessel, a layer of benzene (n=1.50) 6 cm deep floats on water (n=1.33) 4 cm deep. Determine the apparent distance of the bottom of the vessel below the upper surface of the benzene when viewed vertically through air. Ans 7 cm

2. Relevant equations

Snell's law n sin (theta)=n sin (theta)

apparent depth/actual depth = n of air / n of material

3. The attempt at a solution

at first I thought I would solve the equation in parts so that for benzene:

apparent depth = 1(6 cm)/1.5 = 4 cm

and for the water

apparent depth = 1.5 (4 cm)/1.33 = 4.5 cm

adding them together you get 8.5 which is not the right answer. I don't know how you would use Snell's law with not having any theta.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Apparent depth involving benzene on water

**Physics Forums | Science Articles, Homework Help, Discussion**