(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

In a vessel, a layer of benzene (n=1.50) 6 cm deep floats on water (n=1.33) 4 cm deep. Determine the apparent distance of the bottom of the vessel below the upper surface of the benzene when viewed vertically through air. Ans 7 cm

2. Relevant equations

Snell's law n sin (theta)=n sin (theta)

apparent depth/actual depth = n of air / n of material

3. The attempt at a solution

at first I thought I would solve the equation in parts so that for benzene:

apparent depth = 1(6 cm)/1.5 = 4 cm

and for the water

apparent depth = 1.5 (4 cm)/1.33 = 4.5 cm

adding them together you get 8.5 which is not the right answer. I don't know how you would use Snell's law with not having any theta.

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# Apparent depth involving benzene on water

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