Apparent weight on an elevator. Magnitude of its acceleration?

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Homework Help Overview

The problem involves determining the magnitude and direction of the acceleration of an elevator based on the apparent weight readings from a scale inside the elevator. The original poster provides their weight and the scale's reading, indicating a discrepancy that suggests acceleration.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the conversion of weight from pounds to kilograms and the implications of the scale reading. There are attempts to relate the apparent weight to the acceleration of the elevator, with some questioning the calculations and assumptions regarding the direction of acceleration.

Discussion Status

The discussion includes various attempts to calculate the acceleration, with some participants expressing uncertainty about their methods. There is acknowledgment of the need to consider the effects of acceleration on the scale reading, and some guidance is offered regarding the relationship between weight and acceleration.

Contextual Notes

Participants note the importance of understanding whether the elevator is speeding up or slowing down, which affects the interpretation of the scale reading. There is also mention of potential confusion regarding the units and calculations involved.

WPCareyDevil
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Homework Statement


You are standing on a bathroom scale inside an elevator. Your weight is 160 lb, but the reading of the scale is 123 lb.
(a) What is the magnitude and direction of the acceleration of the elevator?
? m/s2
(b) Can you tell whether the elevator is speeding up or slowing down?
do not know
slowing down
speeding up


Homework Equations


weight=mg
ma=ma


The Attempt at a Solution



160lbs = 75.574kg

123lbs: 55.792kg

g= 9.8ms

obviously, the elevator is accelerating downwards, reducing his apparent weight.

his weight when on the ground is 740.625N.

So, 740.625=55.792a
a=13.27475. The question is asking for magnitude, but there is no x component so sqrt(a^2) would still be 13.27475

Obviously, this isn't correct. Can someone point me in the right direction?
 
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WPCareyDevil said:

Homework Statement


You are standing on a bathroom scale inside an elevator. Your weight is 160 lb, but the reading of the scale is 123 lb.
(a) What is the magnitude and direction of the acceleration of the elevator?
? m/s2
(b) Can you tell whether the elevator is speeding up or slowing down?
do not know
slowing down
speeding up


Homework Equations


weight=mg
ma=ma


The Attempt at a Solution



160lbs = 75.574kg

123lbs: 55.792kg

g= 9.8ms

obviously, the elevator is accelerating downwards, reducing his apparent weight.

his weight when on the ground is 740.625N.

So, 740.625=55.792a
a=13.27475. The question is asking for magnitude, but there is no x component so sqrt(a^2) would still be 13.27475

Obviously, this isn't correct. Can someone point me in the right direction?

If it was slowing down while going up it could read the same. All you know is acceleration is less down on the scales.
 
Ahh, you're right. That makes sense - I didnt think of that.


I tried using -13.27, and subtracting 9.8. What am I missing with the calculation?

Thank you for the tip!
 
WPCareyDevil said:
Ahh, you're right. That makes sense - I didnt think of that.I tried using -13.27, and subtracting 9.8. What am I missing with the calculation?

Thank you for the tip!

You can divide by like equations.

9.8/160 = x/123

I know the units are silly but they cancel as long as your acceleration is to be in m/s2

The difference then with 9.8 must be the acceleration in the same direction as g.
 
Thank you so very much!

I was able to figure it out after a bit of tweaking.

This place is the best =D. I've tried to go through answering peoples questions- but I find that I either cannot answer them well enough, or someone has already beat me to it. I'll try to give back as much as I can
 
WPCareyDevil said:
Thank you so very much!

I was able to figure it out after a bit of tweaking.

This place is the best =D. I've tried to go through answering peoples questions- but I find that I either cannot answer them well enough, or someone has already beat me to it. I'll try to give back as much as I can

You're welcome. Glad that it helped. All contributions welcome.

Cheers.
 
WPCareyDevil said:
So, 740.625=55.792a
a=13.27475.
Maybe I'm wrong, but I think it should be 546.762=75.574a so a=7.234.
 

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