Apparentlyx[SUP]2[/SUP]/y + yis the same

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Discussion Overview

The discussion revolves around the algebraic manipulation of the expression x2/y + y and its equivalence to x2 + y2/y. Participants explore the rules of common denominators and the validity of the transformations applied to the expressions.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant claims that x2/y + y is equivalent to x2 + y2/y, citing calculations to support this.
  • Another participant provides a specific example using x = 4 and y = 3 to illustrate the equivalence, showing the calculations step-by-step.
  • A later reply questions the initial claim, suggesting that the correct transformation is actually (x2 + y2)/y instead of the proposed equivalence.
  • There is a mention of multiplying by 1 (y/y) to facilitate the transformation, indicating some participants are trying to clarify the underlying rules of algebraic manipulation.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the equivalence of the expressions, with some asserting the equivalence and others challenging it, leading to an unresolved discussion.

Contextual Notes

There are missing assumptions regarding the conditions under which the transformations are valid, particularly concerning the values of x and y. The discussion also reflects uncertainty about the algebraic rules being applied.

bobsmith76
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apparently

x2/y + y

is the same as

x2+y2/y

I've done the calculations and it's true. But I can't recall the rule that allows you to do that. It's something about common denominators but I can't remember which.
 
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never mind, I got it. if you let x = 4 and y = 3

then

4/3 + 3 = 4/3 + 9/3

and 9/3 = 32/3
 


bobsmith76 said:
never mind, I got it. if you let x = 4 and y = 3

then

4/3 + 3 = 4/3 + 9/3

and 9/3 = 32/3

Do you mean x2{/SUP]/y + y = x2/y + y2/y? If so, you multiply the expression by 1 = y/y (y not zero).
 


bobsmith76 said:
apparently

x2/y + y

is the same as

x2+y2/y
No, it is not. But it is the same as (x2+ y2)/y. I assume that is what you meant.

I've done the calculations and it's true. But I can't recall the rule that allows you to do that. It's something about common denominators but I can't remember which.
"which"? There is only one denominator!

[tex]\frac{x^2}{y}+ y= \frac{x^2}{y}+ \frac{y^2}{y}= \frac{x^2+ y^2}{y}[/tex]
 

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