Applying Coulomb's law to HCl and LiF

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SUMMARY

This discussion focuses on the application of Coulomb's law to the ionic compounds HCl and LiF. The charges used in the examples, 0.17 and -0.17 for HCl, and 1 and -1 for LiF, are derived from the differences in electronegativity between the atoms involved. HCl exhibits a polar covalent bond due to similar electronegativities, while LiF demonstrates a strong ionic bond because of a significant electronegativity difference, resulting in complete electron transfer. The charges are not absolute values but rather approximations based on experimental data and the nature of the bonds.

PREREQUISITES
  • Understanding of Coulomb's law and its formula: Fe = kq1q2/r^2
  • Knowledge of electronegativity and its role in bond formation
  • Familiarity with ionic and polar covalent bonds
  • Basic concepts of atomic structure and electron configuration
NEXT STEPS
  • Research the concept of electronegativity and its measurement methods
  • Study the differences between ionic and covalent bonds in detail
  • Explore experimental methods for determining atomic charges in compounds
  • Learn about the implications of bond polarity on molecular properties
USEFUL FOR

Chemistry students, educators, and anyone interested in understanding the quantitative aspects of chemical bonding and electrostatic forces in ionic and polar compounds.

needingtoknow
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Homework Statement



During a chem lesson my professor was demonstrating Coulomb's law using HCl.

Fe = kq1q2/r^2

so what he did was he replaced q1 and q2 with 0.17 and -0.17.

Then he showed an example with LiF and then replaced q1 and a2 with 1 and -1.

I think he was trying to show us how strong ionic bonds were. Can someone please explain why and how the numbers 0.17 and -0.17 were chosen for HCl and 1 and -1 were chosen for LiF?
 
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LiF has a large difference in electronegativity between the different atoms, the bond is ionic (one electron moves from Li to F, so +1 and -1 are good approximations). For HCl, the electronegativity is more similar, so you just get some polarization. 0.17 is probably the result of a measurement or a simulation, there is no easy way to get that number.
 
So are you saying that +1 and -1 and 0.17 and -0.17 are determined experimentally. Secondly are they charges so does that mean that the lithium atom has a charge of 1 C and the fluorine atom has a charge of -1 C. If so what is the explanation for why the one with the ionic bond had such higher charges? Sorry this entire concept of quantitatively calculating the electrostatic forces involved in a bond is new to me. Thanks again!
 
needingtoknow said:
So are you saying that +1 and -1 and 0.17 and -0.17 are determined experimentally.
I don't say they are, I say it is possible.

Secondly are they charges so does that mean that the lithium atom has a charge of 1 C and the fluorine atom has a charge of -1 C.
Yes. Look up electronegativity. A single fluorine atom has one free spot in the second shell, which has a lower energy level than the single electron in the second shell of lithium (because the lithium nucleus has just 3 positive charges, while fluorine has 9).
 
So electronegativity is the tendency of an atom to attract electrons in a bond. We know that fluorine has a greater electronegativity than lithium and therefore attracts more electrons. In HCl chlorine is more electronegative than hydrogen. For LiF the electronegativity difference is greater making it an ionic bond and HCl a polar attraction. Knowing this why are the charges (q1 and q2) for lithium and fluorine so much greater than the charges for hydrogen and chlorine (q1 and q2)? Is it because the fluorine atom takes more electrons from the lithium (due to its electronegativity) which increases the overall charge of fluorine to 1 C and the overall charge of lithium to -1 C, both of which are numbers that may be determined experimentally? Is my reasoning correct?
 
Knowing this why are the charges (q1 and q2) for lithium and fluorine so much greater than the charges for hydrogen and chlorine (q1 and q2)?
Still due to the different differences in electronegativity (3.0 versus 1.0).
Fluorine takes "exactly" one electron from lithium.
Hydrogen and chlorine share two electrons (one from each atom), both a bit more on the chlorine side.
 

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