Applying Coulomb's law to HCl and LiF

In summary, during a chemistry lesson, the professor demonstrated Coulomb's law using HCl and LiF. The numbers 0.17 and -0.17 were chosen experimentally for HCl, while 1 and -1 were chosen for LiF due to the large difference in electronegativity between the atoms. The electronegativity of an atom determines its tendency to attract electrons in a bond, with fluorine having a higher electronegativity than lithium. This results in higher charges for lithium and fluorine compared to hydrogen and chlorine. The charges for lithium and fluorine are determined experimentally based on the difference in electronegativity.
  • #1
needingtoknow
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Homework Statement



During a chem lesson my professor was demonstrating Coulomb's law using HCl.

Fe = kq1q2/r^2

so what he did was he replaced q1 and q2 with 0.17 and -0.17.

Then he showed an example with LiF and then replaced q1 and a2 with 1 and -1.

I think he was trying to show us how strong ionic bonds were. Can someone please explain why and how the numbers 0.17 and -0.17 were chosen for HCl and 1 and -1 were chosen for LiF?
 
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  • #2
LiF has a large difference in electronegativity between the different atoms, the bond is ionic (one electron moves from Li to F, so +1 and -1 are good approximations). For HCl, the electronegativity is more similar, so you just get some polarization. 0.17 is probably the result of a measurement or a simulation, there is no easy way to get that number.
 
  • #3
So are you saying that +1 and -1 and 0.17 and -0.17 are determined experimentally. Secondly are they charges so does that mean that the lithium atom has a charge of 1 C and the fluorine atom has a charge of -1 C. If so what is the explanation for why the one with the ionic bond had such higher charges? Sorry this entire concept of quantitatively calculating the electrostatic forces involved in a bond is new to me. Thanks again!
 
  • #4
needingtoknow said:
So are you saying that +1 and -1 and 0.17 and -0.17 are determined experimentally.
I don't say they are, I say it is possible.

Secondly are they charges so does that mean that the lithium atom has a charge of 1 C and the fluorine atom has a charge of -1 C.
Yes. Look up electronegativity. A single fluorine atom has one free spot in the second shell, which has a lower energy level than the single electron in the second shell of lithium (because the lithium nucleus has just 3 positive charges, while fluorine has 9).
 
  • #5
So electronegativity is the tendency of an atom to attract electrons in a bond. We know that fluorine has a greater electronegativity than lithium and therefore attracts more electrons. In HCl chlorine is more electronegative than hydrogen. For LiF the electronegativity difference is greater making it an ionic bond and HCl a polar attraction. Knowing this why are the charges (q1 and q2) for lithium and fluorine so much greater than the charges for hydrogen and chlorine (q1 and q2)? Is it because the fluorine atom takes more electrons from the lithium (due to its electronegativity) which increases the overall charge of fluorine to 1 C and the overall charge of lithium to -1 C, both of which are numbers that may be determined experimentally? Is my reasoning correct?
 
  • #6
Knowing this why are the charges (q1 and q2) for lithium and fluorine so much greater than the charges for hydrogen and chlorine (q1 and q2)?
Still due to the different differences in electronegativity (3.0 versus 1.0).
Fluorine takes "exactly" one electron from lithium.
Hydrogen and chlorine share two electrons (one from each atom), both a bit more on the chlorine side.
 

1. How does Coulomb's law apply to HCl and LiF?

Coulomb's law states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. In the case of HCl and LiF, both molecules contain charged particles (H+ and Cl- in HCl, Li+ and F- in LiF) which experience a force of attraction or repulsion according to Coulomb's law.

2. What is the role of distance in Coulomb's law when applied to HCl and LiF?

The distance between the charged particles in HCl and LiF plays a crucial role in determining the strength of the force between them. As per Coulomb's law, the force decreases as the distance between the particles increases. Therefore, the closer the particles are to each other, the stronger the force of attraction or repulsion between them.

3. How does the charge of the particles affect the force between HCl and LiF?

According to Coulomb's law, the force between two charged particles is directly proportional to the product of their charges. This means that the greater the charges on the particles, the stronger the force between them. In the case of HCl and LiF, the charges on the particles are different (H+ and Cl- in HCl, Li+ and F- in LiF), so the force between them will also differ.

4. Can Coulomb's law be used to predict the behavior of HCl and LiF molecules?

Yes, Coulomb's law can be used to predict the behavior of HCl and LiF molecules. The law describes the force between two charged particles, which is an important factor in determining the behavior of molecules. By considering the charges and distance between the particles in HCl and LiF, Coulomb's law can provide insights into their behavior.

5. Are there any limitations to using Coulomb's law to understand HCl and LiF?

While Coulomb's law can provide valuable information about the behavior of HCl and LiF molecules, it is not the only factor that influences their behavior. Other factors such as molecular structure, intermolecular forces, and temperature also play a role. Therefore, Coulomb's law should be used in conjunction with other principles to get a complete understanding of the behavior of these molecules.

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