Applying the Weierstrass M test

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Homework Help Overview

The discussion revolves around applying the Weierstrass M-test to the series \(\sum_{n=1}^{\infty}\frac{1}{n^2}\cos(nx)\) in order to determine its domain of convergence.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the bounding of terms in the series using the sequence \(1/n^2\) and question whether it serves as an appropriate bound. There is also inquiry into the implications of the M-test regarding the domain of convergence.

Discussion Status

Some participants have provided insights on the convergence of the series and its uniform convergence on \(\mathbb{R}\). There is an ongoing exploration of the implications of the M-test and the nature of the convergence.

Contextual Notes

Participants are considering the definitions and properties of the functions involved, as well as the assumptions related to the convergence of the series across the real numbers.

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Homework Statement



[tex]\sum_{n=1}^{\infty}\frac{1}{n^2}cosnx[/tex]

Apply the Weierstrass M-test to the series in order to find the domain of convergence.

Homework Equations





The Attempt at a Solution



Looking at the functions I think I have gottten to the following conclusion,

f1(x)=cosx <= 1

f2(x)=1/4 cos(2x) <= 1/4

I would pick my sequence to be 1/n^2. I am sure that 1/n^2 converges but does it work as a bound on each term? And then what should I do with these two (the series and the sequence of Mk.)?
 
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I am sure that 1/n^2 converges but does it work as a bound on each term?

Looks like it does

[tex]| \frac{1}{n^2} cos(nx) | = \frac{1}{n^2} |cos(nx)|[/tex]

and |cos(nx)| is always less than or equal to 1.
 
That wasn't too bad. But I have a more specific question. Does the M test say that the domain of convergence is R? Since are sequence of functions is defined on R?
 
Yes. The M test says the series converges uniformly on R, so in particular converges on R.
 

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