AQA AS Maths question from '09 paper

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1. Jan 9, 2010

Physssics

Hi,
I have my AS Maths exam on Monday and so I was looking at some previous papers and I couldn't do this question:

The quadratic equation (k+1)x² + 12x + (k-4) = 0 has real roots
(a) Show that k² - 3k - 40 ≤ 0

I don't even understand where to start so I was hoping you could help me.

Thanks!

2. Jan 9, 2010

Dollydaggerxo

I think it may be, that as it has real roots, it must mean that b^2-4ac ≤ 0
so just substitute your values of a b and c into the formula to get k² - 3k - 40

are you sure its -40 and not -140 ?
cause then it would work i think!

3. Jan 9, 2010

Dollydaggerxo

oh no sorry, i forgot to multiply it out, silly me, it would work with 40.
and also 0 ≤ b^2-4ac if it has real roots. sorry i'm a bit foggy on this stuff!

4. Jan 9, 2010

Physssics

Can I ask how how you got the values for a and c?
a=
b= 12
c=
Because I dont understand why the x is there?

By the way -- thanks for the response, I really really appreciate it!

5. Jan 9, 2010

Dollydaggerxo

well you dont have any integer values for the a and c
so instead, you just substitue in the constants before the x^2 for a, and the last value for c

so a would simply be k+1
and c would be k-4

do you remember how to find if an equation has real roots ? that is where the b^2-4ac comes in, you could google it if you don't. If the answer is less than zero it has no real roots, equal to zero it has one real root etc. But yours is telling you it has real roots. plural. so therefore your answer to b^2-4ac is, it must be bigger than 0. Your answer will include k once you multiply it out, and you should get the equation you stated before
k² - 3k - 40 ≤ 0

6. Jan 9, 2010

Physssics

Yeah, I understand now. Thanks alot, I really appreciate it!