Arbitrary Union of Sets Question

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The discussion revolves around the union and intersection of sets defined by natural numbers, specifically where each set \( A_n \) contains a single element \( n \). The union \( \bigcup_{n\in\mathbb{N}} A_n \) is correctly identified as the set of all natural numbers \( \{1, 2, 3, \ldots\} \), while the intersection \( \bigcap_{n\in\mathbb{N}} A_n \) is empty since no single number exists in all sets \( A_n \). Participants express confusion over notation and the completeness of the problem statement. Clarifications on set membership and proving set equality are also discussed. Understanding these concepts is crucial for resolving the initial confusion regarding the notation.
TyroneTheDino
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Homework Statement



For each ##n \in \mathbb{N}##, let ##A_{n}=\left\{n\right\}##. What are ##\bigcup_{n\in\mathbb{N}}A_{n}## and ##\bigcap_{n\in\mathbb{N}}A_{n}##.

Homework Equations



The Attempt at a Solution


I know that this involves natural numbers some how, I am just confused on a notation thing.
Is ##\bigcup_{n\in\mathbb{N}}A_{n}= \left \{ 1,2,3,... \right \}## or##\bigcup_{n\in\mathbb{N}}A_{n}= \left \{ \left\{1\right\},\left\{2\right\},... \right \}##.

To me it makes more sense that this is set of each set of every natural numbers, but somehow I think this is wrong and can't wrap my head around it.
 
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The problem statement is incomplete, it doesn't describe ##A_n##.

In terms of notation,
  • ##x \in \cup_{n\in\mathbb{N}} A_n ## if and only if there exists ##n\in\mathbb{N}## such that ##x\in A_n## (##x## belongs to at least one of the ##A_n##).
  • ##x \in \cap_{n\in\mathbb{N}} A_n ## if and only if ##x\in A_n## for all ##n\in\mathbb{N}## (##x## belongs to all ##A_n##).
 
geoffrey159 said:
The problem statement is incomplete, it doesn't describe ##A_n##.

In terms of notation,
  • ##x \in \cup_{n\in\mathbb{N}} A_n ## if and only if there exists ##n\in\mathbb{N}## such that ##x\in A_n## (##x## belongs to at least one of the ##A_n##).
  • ##x \in \cap_{n\in\mathbb{N}} A_n ## if and only if ##x\in A_n## for all ##n\in\mathbb{N}## (##x## belongs to all ##A_n##).
I updated it to define An.
 
TyroneTheDino said:

Homework Statement



For each ##n \in \mathbb{N}##, let ##A_{n}##. What are ##\bigcup_{n\in\mathbb{N}}A_{n}## and ##\bigcap_{n\in\mathbb{N}}A_{n}##.

Homework Equations



The Attempt at a Solution


I know that this involves natural numbers some how, I am just confused on a notation thing.
Is ##\bigcup_{n\in\mathbb{N}}A_{n}= \left \{ 1,2,3,... \right \}## or##\bigcup_{n\in\mathbb{N}}A_{n}= \left \{ \left\{1\right\},\left\{2\right\},... \right \}##.
##\bigcup_{n\in\mathbb{N}}A_{n}## means ##A_1 \cup A_2 \cup \dots \cup A_n## and similar for the intersection.
TyroneTheDino said:
To me it makes more sense that this is set of each set of every natural numbers, but somehow I think this is wrong and can't wrap my head around it.
 
Ok so you infered that the union was equal to ##\mathbb{N}##. How do you prove that two sets are equal ?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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