Archimedes Principle and Buoyancy

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SUMMARY

The discussion centers on the application of Archimedes' Principle and buoyancy in a physics homework scenario involving a 100g object with a density less than water. The key conclusion is that the measured weight on the triple beam balance will be equal to the combined weights of the water, beaker, and object, as the buoyant force does not affect the balance reading. The relevant equations include Fb = ρVg for buoyant force and Wapt = mg - Fb for the apparent weight.

PREREQUISITES
  • Understanding of Archimedes' Principle
  • Knowledge of buoyant force calculations
  • Familiarity with Newton's Third Law
  • Experience using a triple beam balance
NEXT STEPS
  • Study the derivation and implications of Archimedes' Principle
  • Learn how to calculate buoyant force using different fluid densities
  • Explore applications of Newton's Third Law in fluid mechanics
  • Practice experiments involving triple beam balances and buoyancy
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Students studying physics, educators teaching fluid mechanics, and anyone interested in understanding the principles of buoyancy and balance measurements.

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Homework Statement


A 100g object having a density less than that of water is placed into a beaker half full of water. The beaker is then placed on a triple beam balance. Would be measured weight be equal to, greater than, or less than the weights of the water, the beaker, and the object added together? Explain.

Homework Equations


Fb = ρVg = mf g
Wapt = mg - Fb

The Attempt at a Solution


Would it be equal to as the balance isn't affected by the buoyant force within the beaker? I'm confused.
 
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your attempt is reasonable enough, but Newton's third law would be helpful.
 
Last edited:

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