Archimedes Principle: B = δVg + T

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Discussion Overview

The discussion revolves around Archimedes' Principle, specifically the forces acting on a submerged object in a fluid. Participants explore the concepts of buoyancy, gravitational force, and the relationship between these forces when an object is submerged in water.

Discussion Character

  • Exploratory, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant states that when a piece of metal is submerged, there are two upward forces: buoyancy (B = δVg) and the tension in the string (T).
  • Another participant confirms that the downward force is due to gravity, which is equivalent to the weight of the object.
  • Some participants express confusion regarding the concept of buoyancy, particularly in relation to the forces acting on an imaginary area in the water.
  • A later reply questions the meaning of 'taking out an imaginary area' and suggests that the forces on a submerged object include both buoyant force and the object's weight.

Areas of Agreement / Disagreement

There is some agreement on the nature of the forces acting on the submerged object, but confusion remains regarding the concept of buoyancy and how it relates to the forces described.

Contextual Notes

Participants have not fully clarified the assumptions behind the term 'imaginary area' and how it relates to the forces acting on the submerged object, leading to some ambiguity in the discussion.

Kork
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Hi :)

When I have a container with water and put a piece of metal down in the water while it's hanging on the string, I know that there will be two forces pulling it upwords:

B = δVg
and the string force T

But the force pulling it down, is that the gravitation? Or is it a force that equals to the weight of the piece of metal?
 
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Kork said:
But the force pulling it down, is that the gravitation? Or is it a force that equals to the weight of the piece of metal?
Yes and yes. Gravity pulls the metal downward. (That gravitational force is the weight of the object.)
 
I don't think I quite understand the buoyancy part.

If I tak a cointainer with water and take out an imaginaray area then the forces on the area would be the buoyancy and the gravitationa pulling down? Right?
 
Thank you very much!
 
Kork said:
I don't think I quite understand the buoyancy part.

If I tak a cointainer with water and take out an imaginaray area then the forces on the area would be the buoyancy and the gravitationa pulling down? Right?
Not sure what you mean by 'take out an imaginary area'. The forces on the submerged object will include the buoyant force and the weight of the object. (Maybe you can restate the question.)
 

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