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Are a vector and its derivative perpendicular at all times?

  1. Sep 12, 2015 #1
    i'm dumb, sorry
     

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    Last edited: Sep 12, 2015
  2. jcsd
  3. Sep 12, 2015 #2
    No. What if the vector is not changing direction? In general, the derivative of a vector has components both normal and tangent to the vector.

    Chet
     
  4. Sep 12, 2015 #3

    Nugatory

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    Staff: Mentor

    No. For an obvious example, consider a vector whose magnitude but not direction is increasing as a function of time: ##\vec{F}(t+\Delta{t})-\vec{F}(t)## points in the same direction as ##\vec{F}(t)##. You're thinking of the case in which the magnitude of the vector is constant over time, in which case the derivative must indeed be perpendicular (as in acceleration in the case of uniform circular motion).

    [Edit: Chet got there first but I used more Latex so I still win :smile:]
     
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