Are Commutative Matrices the Key to Solving These Matrix Equations?

  • Thread starter Thread starter Theofilius
  • Start date Start date
  • Tags Tags
    Matrices
Click For Summary

Homework Help Overview

The discussion revolves around proving specific matrix equations involving commutative matrices A and B, specifically focusing on the identities for (A+B)^2 and (A+B)^3. The subject area is linear algebra, particularly matrix operations and properties.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the expansion of (A+B)(A+B) and question the implications of A and B commuting. There are attempts to simplify the expressions based on the commutative property.

Discussion Status

Participants have engaged in expanding the expressions and have begun to simplify them under the assumption that A and B commute. Some guidance has been provided regarding the simplification process, and there is a positive response to the attempts made.

Contextual Notes

The original poster's homework involves proving the identities without providing a complete solution, and participants are navigating through the algebraic manipulations required to reach the proofs.

Theofilius
Messages
86
Reaction score
0

Homework Statement



Proof that if two matrices A and B are commutative, BA=AB, then the equations:

a) [tex](A+B)^2 = A^2 + 2AB + B^2[/tex] ; b)[tex](A+B)^3=A^3+3A^2B+3AB^2+B^3[/tex]

are true.

Homework Equations





The Attempt at a Solution

 
Last edited:
Physics news on Phys.org
Have you tried anything? What do you get if you explicitly expand out the brackets in each case? What happens in the case of A and B commuting?
 
I don't know what do you mean?
 
Theofilius said:
I don't know what do you mean?

What do you get when you multiply out (A+B)(A+B), where A and B are matrices?
 
cristo said:
What do you get when you multiply out (A+B)(A+B), where A and B are matrices?

I get
[tex](A+B)(A+B)=A^2+AB+BA+B^2[/tex]
 
Theofilius said:
I get
[tex](A+B)(A+B)=A^2+AB+BA+B^2[/tex]

Good, now can you simplify this in the case that A and B commute?
 
cristo said:
Good, now can you simplify this in the case that A and B commute?


[tex](A+B)^2=(A+B)(A+B)=A^2+AB+BA+B^2=A^2+2AB (or 2BA) + B^2[/tex]

like this?
 
Theofilius said:
[tex](A+B)^2=(A+B)(A+B)=A^2+AB+BA+B^2=A^2+2AB (or 2BA) + B^2[/tex]

like this?

Correct!

Now, try applying similar techniques to the second question.
 
[tex](A+B)^3=(A+B)(A+B)(A+B)=(A^2+2AB+B^2)(A+B)=A^3+A^2B+2A^2B+2AB^2+B^2A+B^3=A^3+A*AB+2A*AB+2<br /> <br /> AB*B+B*BA+B^3[/tex]
[tex]=A^3+3A^2B+3AB^2+B^3[/tex]

Something like this?
 
Last edited:
  • #10
*Applause*

Huzza, well done!
 

Similar threads

  • · Replies 25 ·
Replies
25
Views
2K
Replies
4
Views
2K
  • · Replies 25 ·
Replies
25
Views
3K
  • · Replies 18 ·
Replies
18
Views
4K
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
10
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 69 ·
3
Replies
69
Views
11K