Are Continuous and Differentiable Functions on [0,1] Closed Under Operations?

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SUMMARY

The discussion confirms that the set of all continuous complex-valued functions on the interval [0,1], denoted as G, is closed under the operation defined by f(x) ∫01 g(t) dt - g(x) ∫01 f(t) dt. Additionally, the set of all differentiable complex-valued functions on [0,1], denoted as H, is closed under the operation fg' - gf'. The derivatives f'' and g'' remain within their respective sets, affirming the closure properties of both G and H under the specified operations.

PREREQUISITES
  • Understanding of continuous complex-valued functions
  • Knowledge of differentiable complex-valued functions
  • Familiarity with integral calculus on the interval [0,1]
  • Basic concepts of derivatives and their properties
NEXT STEPS
  • Explore the properties of continuous functions on closed intervals
  • Study the implications of differentiability in complex analysis
  • Investigate closure properties of function spaces under various operations
  • Learn about the Fundamental Theorem of Calculus and its applications
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Mathematicians, students of calculus, and anyone studying complex analysis or functional analysis will benefit from this discussion.

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If G=the set of all continuous complex-valued functions on the interval [0,1] and [itex]f,g \in G[/itex] then is [tex]\displaystyle f(x) \int^1_0 g(t) \; dt - g(x) \int^1_0 f(t)\;dt[/tex] in G?

If H=the set of all differentiable complex-valued functions on the interval [0,1] and [itex]f,g \in H[/itex] then is [tex]fg' - gf'[/tex] in H?
 
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[itex]\int_0^1 f(x) dx[/itex] and [itex]\int_0^1 g(x)dx[/itex] are numbers so, knowing that f and g are continuous, what can you say about Af+ Bg for constants B and G?

The derivative of f'g+ fg' is f''g+ 2f'g'+ fg''. Knowing that f and g are differentiable what can you say about f'' and g''?
 
HallsofIvy said:
[itex]\int_0^1 f(x) dx[/itex] and [itex]\int_0^1 g(x)dx[/itex] are numbers so, knowing that f and g are continuous, what can you say about Af+ Bg for constants B and G?

The derivative of f'g+ fg' is f''g+ 2f'g'+ fg''. Knowing that f and g are differentiable what can you say about f'' and g''?

Got it. They're both still in the sets.
 

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