Are Continuous and Differentiable Functions on [0,1] Closed Under Operations?

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If G=the set of all continuous complex-valued functions on the interval [0,1] and [itex]f,g \in G[/itex] then is [tex]\displaystyle f(x) \int^1_0 g(t) \; dt - g(x) \int^1_0 f(t)\;dt[/tex] in G?

If H=the set of all differentiable complex-valued functions on the interval [0,1] and [itex]f,g \in H[/itex] then is [tex]fg' - gf'[/tex] in H?
 
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[itex]\int_0^1 f(x) dx[/itex] and [itex]\int_0^1 g(x)dx[/itex] are numbers so, knowing that f and g are continuous, what can you say about Af+ Bg for constants B and G?

The derivative of f'g+ fg' is f''g+ 2f'g'+ fg''. Knowing that f and g are differentiable what can you say about f'' and g''?
 
HallsofIvy said:
[itex]\int_0^1 f(x) dx[/itex] and [itex]\int_0^1 g(x)dx[/itex] are numbers so, knowing that f and g are continuous, what can you say about Af+ Bg for constants B and G?

The derivative of f'g+ fg' is f''g+ 2f'g'+ fg''. Knowing that f and g are differentiable what can you say about f'' and g''?

Got it. They're both still in the sets.