Are functionals united with the vector space which they operate on?

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jaketodd
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Are functionals united with the vector space which they operate on? For example, Physics is a functional of Behavioral Psychology. However, Behavioral Psychology does not include Physics. Am I correct?

Thank you,

Jake
 
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jaketodd said:
Are functionals united with the vector space which they operate on? For example, Physics is a functional of Behavioral Psychology. However, Behavioral Psychology does not include Physics. Am I correct?

Thank you,

Jake
What does this have to do with "vector spaces"? For that matter what does it have to do with mathematics?

Perhaps it would help if you gave a precise definion for your use of "functional" here.
 
I assumed (apparently incorrectly) that functionals could be applied to the abstraction levels of concepts.

Sorry about the confusion; I'm new to these concepts.

What got me asking this question is from Wikipedia: "A spin network, immersed into a manifold, can be used to define a functional on the space of connections on this manifold."
http://en.wikipedia.org/wiki/Spin_network

So I guess what I'm really asking is: Is the map the functional provides, on the space of connections on a manifold, united with the spin network that is immersed into the manifold in order to obtain the functional?

Thanks,

Jake
 
Also, could you give us a mathematical meaning to "united"?
 
zhentil said:
Also, could you give us a mathematical meaning to "united"?

The best I can do is try conceptually: In the concept of spacetime, space is united with time. Does that bring to mind a mathematical representation?

Thank you for bearing with me,

Jake
 
Lol, this is really funny actually. No offense, but you're not making any sense. :) . These math concepts have very precise meanings... if you want a philosophical discussion, you should ask in the philosophy forum. :)
 
But isn't everything representable with math?
 
What can't be defined with math? That's kind of a philosophy question, and I can already hear objections to this thread turning into that. So if you don't want to, don't worry about not responding.