MHB Are Maclaurin Series an Expansion of a Function About 0?

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The Maclaurin series is indeed an expansion of a function around the point 0. It is expressed as f(x) = f(0) + (f '(0) / 1!) * x + (f ''(0) / 2!) * x^2 + (f '''(0) / 3!) * x^3 + ..., capturing the function's behavior near zero. The discussion emphasizes the importance of clarity in forum interactions, encouraging users to post questions in separate threads to maintain focus. Overall, the Maclaurin series serves as a fundamental tool in calculus for approximating functions. Understanding this concept is crucial for deeper mathematical analysis.
physiclawsrule
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Aren't the Maclaurin series an expansion of a function about 0
f(x) = f(0) + (f '(0) / 1!) * x + (f ''(0) / 2!) * x^2 + (f '''(0) / 3!) * x^3 + ...
 
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Hi calculateboard and welcome to MHB!

I've moved your question into its own thread. In future, please post any questions you have in your own thread in order to remain on topic and to help prevent threads from becoming convoluted.

If your question pertains to the topic of another thread then it's o.k. to ask it in that thread. :)

Thanks,

greg1313
 
calculateboard said:
Aren't the Maclaurin series an expansion of a function about 0
f(x) = f(0) + (f '(0) / 1!) * x + (f ''(0) / 2!) * x^2 + (f '''(0) / 3!) * x^3 + ...

Yep. (Nod)
 

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