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Are Noether charges a rep of the generators on the Hilbert space

  1. Feb 11, 2011 #1
    I'm trying to understand the relationship between conserved charges and how operators transform. I know that we can find conserved charges from Noether's theorem. If (for internal symmetries) I call them [tex] Q^a = \int d^3x \frac{\partial L}{\partial \partial_0 \phi_i} \Delta \phi_i^a [/tex] then is it always the case that operators transform like

    [tex] \hat O \rightarrow e^{i t_a Q^a} \hat O e^{-i t_a Q^a} [/tex]

    i.e. are the conserved charges the rep of the generators on the Hilbert space?


    Thanks for any help!
     
  2. jcsd
  3. Feb 11, 2011 #2

    samalkhaiat

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    Science Advisor

    Yes, they do generate the correct transformation on the fields AND satisfy the Lie algebra of the symmetry group. More importantly, they ( in the internal case) DON’T need to be CONSERVED to do the job.

    sam
     
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