Are the Curves 2x^2 + y^2 = 3 and x = y^2 Orthogonal?

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Homework Help Overview

The discussion revolves around determining whether the curves defined by the equations 2x² + y² = 3 and x = y² are orthogonal at their points of intersection. The concept of orthogonality in this context is linked to the slopes of the curves being negative reciprocals of each other at the intersection points.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to find the points of intersection of the two curves before evaluating their slopes. There is an exploration of setting the equations equal to each other and simplifying to find potential x-values. Questions arise about the implications of the resulting equations and the nature of the solutions.

Discussion Status

Participants have identified two points of intersection and are in the process of determining the slopes at these points to assess orthogonality. Some guidance has been provided regarding the differentiation process and the evaluation of slopes at the intersection points.

Contextual Notes

There is an ongoing discussion about the interpretation of the intersection points and the implications of the resulting slopes. Participants are also navigating the challenge of understanding the criteria for orthogonality in the context of the problem.

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Homework Statement


Two curves are said to be orthogonal if their derivatives are opposite reciprocals at the point where the two curves intersect. Are 2x^2 + y^2 =3 and x= y^2 orthogonal?

Homework Equations


I'm not entirely sure what to put here, but I think one relevant thing is to say that the two curves will intersect if they have slopes that are perpendicular to each other. (so m2= -1/m1)

The Attempt at a Solution



Ok- so from what I can piece together, the first thing would be to find out if the two equations would have perpendicular slopes. So I would have to differentiate both equations to find their slopes.

so- 4x+ 2y= 0
and
1=2y

From here though, I am lost. I think y=.5 and x= -.25 and that m1=0 and m2=1. So my hunch is that these lines are not orthogonal. However, I am not sure if this is the correct thing to do. I have searched throughout my book and have not found any example problems worded like this. And related problems I found on the internet didn't make much sense to me.

First post here, so I hope I followed the form correctly. Any help or explanations of how to approach this problem would be very appreciated. Thank you for reading!
 
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Welcome to PF! :)

Well, the first thing I would do is actually find out if the two functions intersect, and if so, where?
 
Char. Limit said:
Welcome to PF! :)

Well, the first thing I would do is actually find out if the two functions intersect, and if so, where?

Ok! And thank you for the welcome! =)

ok. So I'll need to set them equal to each other, right? So I'd have 2x^2 + y^2 -3= y^2 -x

Which can simplify to 2x^2 + x -3= 0

So...to solve this I'd need to use the quadratic formula, correct? Which would give me x= 1 and -3/2.

From there I tried plugging the answers in. If I choose x=1, both equations turn into 1= y^2 so is this the value I need?
 
What does 1 = y^2 imply about what y equals? The coordinates of intersection will have 1 x value but 2 y values
 
Clever-Name said:
What does 1 = y^2 imply about what y equals? The coordinates of intersection will have 1 x value but 2 y values

I would think it means Y can equal 1 or -1 and either squared would equal one. making he equation true. (1=1) Is this right?
 
Yep! So that gives you two points of intersection: (1,1) and (1,-1)

Now go back to your criteria for orthogonality using those points!
 
Clever-Name said:
Yep! So that gives you two points of intersection: (1,1) and (1,-1)

Now go back to your criteria for orthogonality using those points!
Ok! So going back to the original 2 equations, I now must differentiate them and plug in the given values to see if the slopes are perpendicular to each other. When i plugged in (1,1) I received the slopes 6 and 1.

I then plugged in (1, -1) and got the slopes 2 and -3. Based of this, I can say that the lines are not perpendicular and therefore not orthogonal...right? =)
 

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