Are the phosphate groups of ATP protonated at pH = 7?

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SUMMARY

At pH 7, the phosphate groups of ATP are predominantly deprotonated, with more than half of the groups being quadruply deprotonated due to the pKa values of the phosphate groups. The first dissociation of phosphoric acid (H3PO4) occurs at a pKa of approximately 2, while the second dissociation is around pKa 6.8, indicating that at physiological pH, ATP loses three protons. Additionally, ATP is typically complexed with magnesium ions (Mg2+), which plays a crucial role in reactions involving phosphate transfer.

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  • Understanding of acid-base chemistry, specifically pKa values.
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Homework Statement



The problem states: "Draw the chemical structure of ATP at a pH of 7.

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The Attempt at a Solution



The textbook diagrams the phophate groups as unprotonated, but since H3PO4 has a pKa of <7, I was thinking that maybe each phosphate group would have lost one hydrogen atom?
 
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You mean lost a hydrogen ion, i.e. a proton, so they are deprotonated as you say.
I think inorganic phosphate is a good guide: it is a strongish acid for the first dissociation (pK ca. 2) then the second dissociation is at near neutral pH's pK ca. 6.8.

In ATP correspondingly 3 protons are always lost at physiological pH's. The fourth pK I have seen given as various values 6.6 up to 6.95. So at intracellular pH of about 7 rather more than half should be quadruply deprotonated. Then in life it is all complexed with Mg2+ anyway. As far as I know there is not a single reaction involving phosphate or pyrophosphate transfer, which must be at least half of all important reactions, that occurs in the absence of magnesium.
 

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