- #1

vande060

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## Homework Statement

Prepare 500ml of a reaction buffer containing .82% MgCl

_{2}, 62.5 mM glucose, 950 ATP, and 100mM Tris -Cl, pH 7.8 Use the stock solutions you have prepared

we had to prepare in previous problems:

500ml 1.75M glucose

25mL 2.5% glucose

2L of 1.8 Tris, pH 8.5

## Homework Equations

C1V1 = C2V2

Pka Tris = 8.1

glucose mol mass = 180.16

ATP mol mass = 507.8

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## The Attempt at a Solution

my calculation for MgCl

_{2}:

.82% = .82g/100ml = 8.2g/L

15% = 15g/100ml = 150g/L

C1V1=C2V2

150*x = 8.2*500

x = 28mL stck 15% MgCl

_{2}

My calculation for glucose

1.75M glucose = 315g/L

62.5mM = 11.2 g/L

C1V1=C2V2

11.2*500 = 315*x

x = 17.7 ml 1.75M glucose stock

Here is my calculation for ATP

5mM ATP = 3g/L

950nM ATP = .00048g/L

C1V1=C2V2

3*x = .00048*500

x =.08ml of stocK 5mM ATP

My calculation for the Tris I am not sure about, can I use my original pH 8.5 solution the prof asked me to prepare, or do I have to start over with the Tris acid and base components and use henderson H equation? does this all look right so far?