Are These Negations of Limits and Continuity Correct?

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The discussion focuses on the negation of the mathematical concepts of limits and continuity for a function f defined on an interval I. It establishes that "f does not have limit L at c" is correctly negated by stating that for every number L, there exists an epsilon > 0 and a sequence {x_n} converging to c such that |f(x_n) - L| > epsilon. Additionally, the negation of continuity at c is confirmed as there exists an epsilon > 0 and a sequence {x_n} converging to c such that |f(x_n) - f(c)| > epsilon for every n.

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Let f:I->R and let c in I. I want to negate the statements: "f has limit L at c" and "f is continuous at c". Are these correct?

f does not have limit L at c if there exists e>0 such that for some sequence {x_n} converging to c, |f(x_n)-L|>e for every n.

f is not continuous at c if there exists e>0 such that for some sequence {x_n} converging to c, |f(x_n)-f(c)|>e for every n.

edit: also, what is the negation of "f has a limit at c"?
 
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Yes, those will work, since "for all sequences {a_n} converging to c, the sequence {f(x_n)} converges to L", though not the standard definition of limit, is equivalent to it.

As far as "f does not have a limit at c" (as opposed to "f does not have limit L at c"), you just have to add "for every L":
"For every number L, there exist an epsilon> 0 and a sequence {x_n} that converges to c, such that |f(x_n)- L|> epsilon."
 
Thanks a lot.
 

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