1. The problem statement, all variables and given/known data Which of the following Nuclear Reactions are allowed? A) e- + p --> [tex]\mu[/tex]- + p B) n --> p + [tex]\pi[/tex]- C) K- + p --> (anti)k0 + n 2. Relevant equations While I don't know if there are any relevant equations, I know that there are several conservation laws that are required to make a reaction acceptable. 3. The attempt at a solution A) e- + p --> [tex]\mu[/tex]- + p I ran through a few conservation rules. - I said that the Baryon number on each side was 1, so Baryon number is conserved. - e- and mu are both leptons, so lepton number is conserved - charge is conserved On this problem I am leaning towards it being correct, but the reason I am hesitant to say so is because I am worried I am missing a conservation law somewhere. B) n --> p + [tex]\pi[/tex]- - Again, baryon number is conserved - lepton number is conserved - mesons don't require conservation - the charge is conserved. Again, I lean towards this being correct, but I am kind of worried about how a neutron results in the formation of a proton and pi- particle, for a number of different reasons. First, I've always associated the change of the charge of a nucleon with the release or absorption of an electron - I have never heard of a different lepton taking its place. Second, there is a really large mass discrepancy, but I think that might be solvable by the fact that the neutron could have a large kinetic energy and the p and pi- particles not moving as much. C) K- + p --> (anti)k0 + n -Baryon number is conserved -Lepton number is conserved -Charge is conserved Am I over exaggerating in worrying that these reactions are not valid? I feel like there are too many pot-holes for a reaction to fall in, so I am really hesitant to give a definite answer. Would anyone be able to steer me in the right direction if more conservation laws apply here?