Area B/w Curves: y=(secx)^2/4 & 4(cosx)^2

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SUMMARY

The discussion focuses on calculating the area between specific curves: 1) \(y=\frac{(\sec x)^2}{4}\) and \(y=4(\cos x)^2\), 2) \(y=e^x\), \(y=e^{-4x}\), and \(x=\ln 4\), and 3) \(y=5\cos x\) and \(y=5\cos(2x)\) over the interval \(0 \leq x \leq \pi\). The area between two functions \(y=f(x)\) and \(y=g(x)\) on the interval \([a,b]\) is determined using the integral \(\int_a^b (f(x) - g(x)) \, dx\). Participants are encouraged to apply this formula to find the areas between the specified curves.

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Determine the area between:

1.) y=((secx)^2)/4 and y=4(cosx)^2

2.) y=e^x , y=e^-4x , and x=ln4

3.) y=5cosx and y=5cos(2x) for 0≤x≤pi
 
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brickair said:
Determine the area between:

1.) y=((secx)^2)/4 and y=4(cosx)^2

2.) y=e^x , y=e^-4x , and x=ln4

3.) y=5cosx and y=5cos(2x) for 0≤x≤pi

The area between $y=f(x)$ and $y=g(x)$ on the interval $[a,b]$, when $f(x) \geq g(x)$ is euqal to $\displaystyle{\int_a^bf(x)-g(x) dx}$.

Can you apply this in your case?
 
brickair said:
Determine the area between:

1.) y=((secx)^2)/4 and y=4(cosx)^2

2.) y=e^x , y=e^-4x , and x=ln4

3.) y=5cosx and y=5cos(2x) for 0≤x≤pi

Hello and welcome to MHB!

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b) Show what you have tried, as this gives our helpers a better idea where you are stuck and how best to help. Our goal here is to maximize the learning for the person asking the question by getting them involved in the solution process.
 

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