MHB Area Inside Circle x^2+y^2=a^2 Above b=7

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The discussion focuses on finding the area inside the circle defined by the equation x^2+y^2=a^2, specifically above the line y=b, where -a ≤ b ≤ a. There is a suggestion that the original question may contain a typo regarding the line's position. Participants clarify that the area can be computed either through integration or geometrically. The geometric method is highlighted as simpler, referencing the area of a triangle formula. The conversation emphasizes the need for clarity in the problem statement to proceed effectively.
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Find area inside circle x^2+y^2=a^2, above 7=b, -a \le b \le a ?? i think f of y right?
(-a to a) minus (-a to b)?
 
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wonguyen1995 said:
Find area inside circle x^2+y^2=a^2, above 7=b, -a \le b \le a
Maybe it's a typo and should read "above $y=b$". That is, find the area inside the circle $x^2+y^2=a^2$ that is located above the line $y=b$, where $-a\le b\le a$.

wonguyen1995 said:
?? i think f of y right?
(-a to a) minus (-a to b)?
Sorry, I don't understand your remark.
 
Evgeny.Makarov said:
Maybe it's a typo and should read "above $y=b$". That is, find the area inside the circle $x^2+y^2=a^2$ that is located above the line $y=b$, where $-a\le b\le a$.

Sorry, I don't understand your remark.

That is it, i mistake.
so can you help me??
 
Do you need a solution that uses integral? It's easier to find the area geometrically as described in Wikipedia using the fact that the area of a triangle with sides $u$ and $v$ and angle $\varphi$ between them is $\frac{1}{2}uv\sin\varphi$.
 

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