Area of a Gold Leaf? | Calculate with Density

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SUMMARY

The discussion focuses on calculating the area of a gold leaf and the length of a cylindrical fiber made from gold, utilizing its density of 19.32 g/cm³. For part (a), the area of the gold leaf is derived from the formula for volume, V = mass/density, and the relationship V = area × thickness. For part (b), the length of the fiber is calculated using the same volume and the formula for the volume of a cylinder, V = πr²h. The calculations confirm that understanding the geometric properties of solids is essential for solving these problems.

PREREQUISITES
  • Understanding of density and its formula (ρ = m/V)
  • Knowledge of geometric volume formulas for prisms and cylinders
  • Familiarity with unit conversions, particularly between grams and cubic centimeters
  • Basic algebra skills for manipulating equations
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  • Learn how to derive area from volume using geometric principles
  • Study the properties of gold and its applications in materials science
  • Explore advanced volume calculations for irregular shapes
  • Investigate the physical properties of metals, focusing on ductility and density
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Students in physics or materials science, educators teaching geometric volume calculations, and anyone interested in the properties of metals and their applications in practical scenarios.

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Homework Statement



Gold, which has a density of 19.32 g/cm^3, is the most ductile metal and can be pressed into a thin leaf or drawn out into a long fiber. (a) If a sample of gold, witha mass of 27.63g, is pressed into a leaf 1.000 µm thickness, what is the area of the leaf? (b) If, instead, the gold is drawn out into a cylindrical fiber of radius 2.500 µm, what is the length of the fiber?


Homework Equations



ρ=m/V and others?

The Attempt at a Solution



Not sure what to do. Got volume but how do i use that to get area? I also do not know what equations would apply to a gold leaf.
 
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isnt volume =area * thickness
 
Punkyc7 said:
isnt volume =area * thickness

Yes, if i assume that it is a cube or rectangular prism.
is that right?
 
In general, a prism does not have to be rectangular in cross section for the volume relation to hold, so long as all cross sections are similar. For the gold leaf, the thickness is so small, it would be reasonable to assume that the areas of the front and back of the leaf are equal, hence the leaf could be considered to be a very short prism.
 

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