Area of a Gold Leaf? | Calculate with Density

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Homework Help Overview

The problem involves calculating the area of a gold leaf based on its mass and density, as well as determining the length of a cylindrical fiber made from the same mass of gold. The subject area relates to concepts of density, volume, and geometric properties of solids.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between volume, area, and thickness, with one participant noting the formula for volume as area times thickness. There is uncertainty about how to apply this to find the area of the gold leaf and what equations are relevant.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the volume formula and its application to the problem. Some guidance has been offered regarding the assumptions that can be made about the shape of the gold leaf.

Contextual Notes

Participants are navigating the constraints of the problem, including the specific dimensions provided and the properties of gold. There is a lack of consensus on the best approach to take, as well as uncertainty about the equations that should be used.

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Homework Statement



Gold, which has a density of 19.32 g/cm^3, is the most ductile metal and can be pressed into a thin leaf or drawn out into a long fiber. (a) If a sample of gold, witha mass of 27.63g, is pressed into a leaf 1.000 µm thickness, what is the area of the leaf? (b) If, instead, the gold is drawn out into a cylindrical fiber of radius 2.500 µm, what is the length of the fiber?


Homework Equations



ρ=m/V and others?

The Attempt at a Solution



Not sure what to do. Got volume but how do i use that to get area? I also do not know what equations would apply to a gold leaf.
 
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isnt volume =area * thickness
 
Punkyc7 said:
isnt volume =area * thickness

Yes, if i assume that it is a cube or rectangular prism.
is that right?
 
In general, a prism does not have to be rectangular in cross section for the volume relation to hold, so long as all cross sections are similar. For the gold leaf, the thickness is so small, it would be reasonable to assume that the areas of the front and back of the leaf are equal, hence the leaf could be considered to be a very short prism.
 

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